Question

A particle is moving along a straight line with constant acceleration. In an interval of T seconds it moves D meters; in the next interval of 3T seconds it moved 9D metres. How far does it move in a further of T seconds?

Answer 1

@amistre64 @ParthKohli @waterineyes

Answer 2

@TuringTest

Answer 3

@waterineyes

Answer 4

Not good at physics brother..

Answer 5

oh...no probs:)

Answer 6

In first T second, the particle covers D meters and in (T+3T) seconds it covers (D+9D) meters.
So, when t=T, S=D
when t=4T, S=10D

Now use relation S=(1/2)at^2.
Find a in terms of T and D

Now calculate S for 5T seconds and then subtract distance moved in 4T seconds (i.e. 10D) from it. That will give you the distance moved in a further of T seconds!

Answer 7

can u shw the working

Answer 8

Try doing it yourself. Its way too easy and i have given you the process,