Question

Type the equation of the given line in standard form.
The line including two points (6, 4) and (-5, 3).

Thanks for the help!

Answer 1

Line with two points is given by:

\[\large \frac{y - y_1}{y_2 - y_1} = \frac{x- x_1}{x_2 - x_1}\]

Use this to solve...

Answer 2

But I only have two y points. But I have to substitute in 3? Sorry, I'm just confused..

Answer 3

these are the points in your question
\[ (x _{1},y_{1}) (x _{2},y_{2})\]
just substitute to the formula

Answer 4

y-4=((3-4)/(-5-6))(x-6)
y-4=(1/11)(x-6)

Answer 5

the equation of the line passing through two points (x1,y1) and (x2,y2) and slope m is:
y-y1=m(x-x1)
where m is (y2-y1)/(x2-x1)

Answer 6

@kaiz122 I know to substitute those in. But in the topmost equation, there is just plain x & y and I don't know what to put into those. Does that make sense?

Answer 7

those are constants @theequestrian

Answer 8

and nitz have already given the answer

Answer 9

Ohhhh. Right. That was quite embarassing. Lol. Thanks though :)

Answer 10

np. :)

Answer 11

Leave x and y as such they are arbitrary points.

Answer 12

\[\frac{y-4}{3 - 4} = \frac{x-6}{-5-6} \implies \frac{y-4}{-1} = \frac{x-6}{-11}\]

Can you solve it now??

Answer 13

Oh, okay. & I think I can. :)

Answer 14

Go ahead..

Answer 15

I got y-4=(1/11)(x-6) once I solved it, like what nitz said.

Answer 16

multiply by 11 both the sides and tell me what do you get..

Answer 17

I got 11y-44=x-6

Answer 18

No, wait. I got 11y-44=11x-66

Answer 19

Previous one is right..

Answer 20

On right hand side 11 and 11 will get cancel so need to multiply 11 with it also..

Getting??

Answer 21

But don't I have to distribute the 11 to the x-6 too?

Answer 22

Why you distribute ??

there is 11 in the denominator ..

Don't you think both the 11 will get cancel??

Answer 23

Getting ??

tell me..

Answer 24

Oh. I thought it would only cancel for the 1/11 * 11. But I see what you are saying now

Answer 25

Or I will show you??