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OpenStudy (anonymous):
need help?
OpenStudy (anonymous):
\[\left( 2*5^{2}\right)^{5}\div5^{10}*2^{3}\]
thats the problem right?
OpenStudy (liliakarina):
Yes, that is
OpenStudy (anonymous):
ok solve the parenthesis first.
OpenStudy (anonymous):
so it eould be\left( 2*25 \right)\]\[^{5}
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OpenStudy (anonymous):
\[50^{5}\]
OpenStudy (anonymous):
pemdas. exponets is the e. so you do \[5^{2}\] not \[\left( 2*5 \right)^{2}\]
OpenStudy (liliakarina):
Ah, okay
OpenStudy (anonymous):
sorry if ui confused you. but it the 5 first and from there you multiply that 2 so its 50 to the fifth power divided by the rest of the prob
OpenStudy (liliakarina):
So, its 50^5/10^13
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OpenStudy (anonymous):
ok now on the bottom you have\[5^{10}*2^{3}\]
OpenStudy (anonymous):
naw not that.
OpenStudy (anonymous):
ok now the
\[2^{3}\] equals 8 sonow the bottom is \[5^{10}*8\]
OpenStudy (anonymous):
so now the prob is \[50^{5}\div5^{10}*8\]
OpenStudy (liliakarina):
Right. Then would it be 40^10 ?
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OpenStudy (anonymous):
ok you cant multipy bases.
OpenStudy (liliakarina):
So it cant get any more simplified?
OpenStudy (anonymous):
\[2*3^{3}\]is six cubed but \[2*3^{3}\] is difeferent cuz it would be 2*9=18 but back to the prob. it can... there a shortcut in to doing it without solvibng all exponets but i dont remember it.