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OpenStudy (anonymous):
OpenStudy (anonymous):
operate D-3 on the second equation and add it to the first equation.
OpenStudy (anonymous):
@ranyai12 there?
OpenStudy (anonymous):
yes i am
OpenStudy (anonymous):
and what do you mean by operate D-3 on the second equation?
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OpenStudy (anonymous):
just multily the LHS by D-3 and operate (d/dt-3) on RHS
OpenStudy (anonymous):
I'm sorry but is there any way you can show me instead on typing it. I tend not to understand math unless I see an example
OpenStudy (anonymous):
\[(D-3)(D^{2}x+(D+3)y)=(D-3)(t^{2}+3t)\]
\[=> (D^{3}-3D^{2})x+(D^{2}-9)y=\frac {d}{dt}(t^{2}+3t)-3(t^{2}+3t)=3-3t^{2}-7t\]
now subtract the first equation from this equation.
OpenStudy (anonymous):
so sint-3-3t^2-7t?
OpenStudy (anonymous):
@vamgadu is that what we're supposed to do? sorry i just want to make sure
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