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Find the sum of the convergent series
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\[\sum_{0}^{\infty} 9(\frac{4}{5})^n\]
Since 4/5 < 1 we use a/(1-r) right?
\[\frac{9}{\frac{5}{5} - \frac{4}{5}}\]
\[\frac{9}{\frac{1}{5}} = 9 * 5/1 = 45?\]
\[9*\frac{1}{1-\frac45}\] yes, since 4/5 is less than 1 it goes to zero in the end and we are left with the denom
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wuh?
i simply agreed with your assessment ...
the denom?
oh okay....
did I calculate this correctly?
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yes, but a wolf chk would be more assuring :)
http://www.wolframalpha.com/input/?i=sum+%28from+0+to+inf%29+%289*%284%2F5%29%5En%29
Oh I was going to do it... Woot I'm correct :D
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