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Chemistry 17 Online
OpenStudy (anonymous):

WANTED: zepp

OpenStudy (anonymous):

OpenStudy (anonymous):

@zepp

OpenStudy (anonymous):

let me try..

OpenStudy (anonymous):

In order to find the limiting reagent..you need to know the moles of the 2 right ?

OpenStudy (zepp):

Omg I'm wanted :<

OpenStudy (anonymous):

XD

OpenStudy (anonymous):

ok so i found that CO = 12.71 mol and H2 = 32.5 mol

OpenStudy (anonymous):

how do i know which one is the limiting reagent ?

OpenStudy (anonymous):

hello? earth to zepp x.X

OpenStudy (anonymous):

@zepp wtf! where did u went?

OpenStudy (zepp):

Limiting reagent is something that's necessary to the reaction; aka one thing that stops the reaction if disappears Sorry - afk :(

OpenStudy (zepp):

So in this case, it would be methanol

OpenStudy (anonymous):

how the hell u get methanol, isn't it between CO and H2 ?

OpenStudy (zepp):

Oh lol, read the first question

OpenStudy (anonymous):

what is the limiting reagent?

OpenStudy (anonymous):

dont you gotta find the mol of the 2 first then compare which one is smaller or something?

OpenStudy (zepp):

It would be H2 in this case

OpenStudy (anonymous):

nooooo zepp! you gotta work it out first =.=

OpenStudy (anonymous):

stop guessing

OpenStudy (zepp):

Well, C = 12g; O = 16g CO = 12 + 16 = 28g H2 = 1.01 * 2 = 2.02g 2 H2 = 2.02 * 2 = 4.04g 356/28 = 12.71 65/4.04 = 16.9 Seems to have some H2 excess :D Limiting reagent = Carbon Monoxide

OpenStudy (anonymous):

see...now it's correct haha :D

OpenStudy (anonymous):

wait so when you found the mol of the two, and which ever the lesser? that mean it's a limiting reagent ?

OpenStudy (anonymous):

how do you calculate the excess ?

OpenStudy (anonymous):

prior to question 3

OpenStudy (zepp):

Calculate excess?

OpenStudy (zepp):

Easy, take the limiting reagent's ratio and compare to what quantities of H2 will really need to react all the limiting reagent.

OpenStudy (anonymous):

show work please :D

OpenStudy (zepp):

.-.

OpenStudy (anonymous):

cmon...do it real quick

OpenStudy (zepp):

alright alright

OpenStudy (anonymous):

im not even studying my midterm review..and sitting here trying to do some stoicheometry -.-

OpenStudy (anonymous):

time is tickling....tick tack tick tack...tick tack....wake up zepp.. =.=

OpenStudy (zepp):

http://puu.sh/L8eU There

OpenStudy (anonymous):

ahh u coulda take me to that program with cha...:<

OpenStudy (anonymous):

how the hell u get 9.63.....65-51.37 = 13.63 zepp ! lol lol

OpenStudy (zepp):

http://puu.sh/L8hi ;[ I typed in 61, lol

OpenStudy (anonymous):

grr... i will bite u :))

OpenStudy (anonymous):

I'm ready for the review session... @.@!

OpenStudy (anonymous):

hey..stop afk on me plz! !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

hold on i need to afk for a minute o_0

OpenStudy (zepp):

o.O

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