Chemistry
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OpenStudy (anonymous):
WANTED: zepp
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OpenStudy (anonymous):
OpenStudy (anonymous):
@zepp
OpenStudy (anonymous):
let me try..
OpenStudy (anonymous):
In order to find the limiting reagent..you need to know the moles of the 2 right ?
OpenStudy (zepp):
Omg I'm wanted :<
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OpenStudy (anonymous):
XD
OpenStudy (anonymous):
ok so i found that CO = 12.71 mol
and H2 = 32.5 mol
OpenStudy (anonymous):
how do i know which one is the limiting reagent ?
OpenStudy (anonymous):
hello? earth to zepp x.X
OpenStudy (anonymous):
@zepp wtf! where did u went?
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OpenStudy (zepp):
Limiting reagent is something that's necessary to the reaction; aka one thing that stops the reaction if disappears
Sorry - afk :(
OpenStudy (zepp):
So in this case, it would be methanol
OpenStudy (anonymous):
how the hell u get methanol, isn't it between CO and H2 ?
OpenStudy (zepp):
Oh lol, read the first question
OpenStudy (anonymous):
what is the limiting reagent?
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OpenStudy (anonymous):
dont you gotta find the mol of the 2 first then compare which one is smaller or something?
OpenStudy (zepp):
It would be H2 in this case
OpenStudy (anonymous):
nooooo zepp! you gotta work it out first =.=
OpenStudy (anonymous):
stop guessing
OpenStudy (zepp):
Well, C = 12g; O = 16g
CO = 12 + 16 = 28g
H2 = 1.01 * 2 = 2.02g
2 H2 = 2.02 * 2 = 4.04g
356/28 = 12.71
65/4.04 = 16.9
Seems to have some H2 excess :D
Limiting reagent = Carbon Monoxide
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OpenStudy (anonymous):
see...now it's correct haha :D
OpenStudy (anonymous):
wait so when you found the mol of the two, and which ever the lesser? that mean it's a limiting reagent ?
OpenStudy (anonymous):
how do you calculate the excess ?
OpenStudy (anonymous):
prior to question 3
OpenStudy (zepp):
Calculate excess?
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OpenStudy (zepp):
Easy, take the limiting reagent's ratio and compare to what quantities of H2 will really need to react all the limiting reagent.
OpenStudy (anonymous):
show work please :D
OpenStudy (zepp):
.-.
OpenStudy (anonymous):
cmon...do it real quick
OpenStudy (zepp):
alright alright
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OpenStudy (anonymous):
im not even studying my midterm review..and sitting here trying to do some stoicheometry -.-
OpenStudy (anonymous):
time is tickling....tick tack tick tack...tick tack....wake up zepp.. =.=
OpenStudy (anonymous):
ahh u coulda take me to that program with cha...:<
OpenStudy (anonymous):
how the hell u get 9.63.....65-51.37 = 13.63 zepp ! lol lol
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OpenStudy (anonymous):
grr... i will bite u :))
OpenStudy (anonymous):
I'm ready for the review session... @.@!
OpenStudy (anonymous):
hey..stop afk on me plz! !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
OpenStudy (anonymous):
hold on i need to afk for a minute o_0
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OpenStudy (zepp):
o.O