Question

Let (-7,2) be a point on the terminal side of theta. Find the exact values of cos, csc, and tan.

Answer 1

Can you solve this system of equations?
\[x^2 + y^2 = 1\]\[y = -\frac27x\]

Answer 2

No sorry I forgot how to do that:/ do you have any idea how I should start mine?

Answer 3

Ok. You have to substitute in -2/7x for y in the first equation.
\[x^2 + (-\frac27x)^{2} = 1\]

Answer 4

Okay I get that part but how do I draw it on the terminal side of the graph? And find the other answers?

Answer 5

You have to solve for x here. Then plug both back in to solve for y.
Then, you have to pick the coordinate that is in the same quadrant as (-7, 2) which is Quadrant II. Using that coordinate, you have your sin and cos, x and y respectively, and you can solve for csc and tan :)

Answer 6

*sin and cos, y and x respectively.

Answer 7

Can you show me step by step? I forgot completely how to do this I know how to finish it after I draw the triangle in the second quadrant I just don't know what the lengths are! Thank you so much!!!!!

Answer 8

or try this... since you know that -7,2 is in QII, draw it out and use reference angles...