graph the line: y=-x-2
This is in slope intercept form already, so can you identify the slope? What is y when x is 0?
-2?
Look at the coefficient of x. Slope intercept form is y = mx + b where m is the slope of the line.
what do you mean by the coefficient?
The coefficient is the constant in front of the variable x.
so in that case it would be what? sorry im not good at slope
For instance, if you have an equation like: \[-5x^3 + 15x^2 + 5\] Then the coefficients are -5, 15, and 5.
So if you have -x, the coefficient is an assumed (-1) since -1 * x = -x
oh ok so -3 then?
No, you're trying to subtract the 2 also. In slope intercept form, the slope is simply -1. This comes from the (-1)x term.
so on the x axis its -1?
Right, so this means that (depending on what terminology your class is using) the rise/run = -1.
but i have to plot it here i show the pic
Correct. I'm not going to just draw it for you. But you can see that given the equation that the slope is -1, correct?
ya
So this means at any point on the line, that to get to the next point you either must move up (+)1 and left (-)1, or down (-) 1 and right(+) 1. It doesn't matter which. Does it make sense?
|dw:1343102059980:dw| does this work?
I can't tell exactly what you're doing. This may not be the graph of that PARTICULAR line, but it appears to have a -1 slope. Now to figure out what's going on, you can easily just plug 0 in for x and see what y is.
oh ok thank you!
Do you see? Let's see what you got.
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