simplify the radical exspression
where are you getting confused here?
i got
i just wanna see if im correct @lgbasallote
i dont think that's right
\[\sqrt{180h^4} = \sqrt{36 \times h^2 \times h^2 \times 5}\] does that help?
im confused now
still need help?
@Nali yes please
\[\sqrt{180h^4}=\sqrt{6\times 6\times h^2 \times h^2 \times 5}=6h^2 \sqrt{5}\]
ok when u simplify a rational expression u r looking for perfect squares such as 4=2x2 9=3x3 16=4x4
@nphuongsun93 thank you . that explains it better !
ok so u get it
@Nali yes i do. thanks though !
ur welcome
@Nali actually that is'nt right. could you explain please
yes do u see my first comment about the perfect squares
@Nali Yes
it's just missing a -3 there
should be \[-3 \times 6h^2 \sqrt 5\]
ok from there in ur question we are trying to find for 180 a perfect square that it can be break into such as 180 divided by 4 = 45 180 divided by 36= 5 do u see where iam going with this
what they said a while ago was just \[\sqrt{180h^4}\]
@megannn do u get his explainition
@Nali yess i see, and no i dont get the other explanation
so do u want me to continue?
yes please. i want to know the steps of it
ok so lets leave the h for a second i just want u to understand the steps \[\sqrt{180}= \sqrt{36}\sqrt{35}\] \[\sqrt{180}=6 times \sqrt{5} \] \[\sqrt{180}= 6 \sqrt{5}\] do u get what i am doing?
in the first step i meant this \[\sqrt{180}= \sqrt{36}\sqrt{5}\] not 35
@megannn
okay i get it , at first i didnt get it because you said 35
ok so i will continue with the h
okay.
\[\sqrt{180}= 6\sqrt{5h ^{4}}= 6\sqrt{5h ^{2}h^{2}}\] Now u know how when theris an x^2 under a squreroot it becumes only x
thats what i came up with
yes that is one step away form the correct answer
do u want me to show u why
sure ! @Nali
leaving the numbers out to make it easier |dw:1343030046984:dw|
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