Question

Circle S has an equation of (x – 16)2 + (y – 9)2 = 4. What is the center and radius of circle S?

Answer 1

General equation of the circle is given by:

\[\large (x-h)^2 + (y-k)^2 = r^2\]

Here (h,k) is center

and r is radius..

Can you compare for the values of h k and r??

Answer 2

You can write your equation as:

\[\large (x-16)^2 + (y-9)^2 = 2^2\]

Now compare it with general equation and tell me the values of h, k and r...

Answer 3

Huh?

Answer 4

9^2 = 81 and is the radius?

Answer 5

Im not comprehending.

Answer 6

Right hand side 4..

Answer 7

OH

Answer 8

I see it!

Answer 9

See tell me what I have written and what your equation is can you see they are similar???

Answer 10

They are both negative. I got Center: (-16, -9); Radius: 4

Answer 11

I show you more clearly:

\[\large (x-h)^2 + (y-k)^2 = r^2\]

\[\large (x-16)^2 + (y-9)^2 = 2^2\]

They are similar or not??

Answer 12

They are you plug it in.

Answer 13

no they are not negative..

if you closely look then h is 16 and not -16..

look it once more..
because there is minus sign already in front of it..

Answer 14

You sure?

Answer 15

So its positive? Center: (16, 9); Radius: 4

Answer 16

Radius in not 4..

Check it once again...

Answer 17

Is it 2?