Consider the gaseous equilibrium
$$2HI(g) \rightleftharpoons
H_2(g) +I_2(g)$$

the addition of more hydrogen will shift the equilibrium to the left right? If yes I don't get why; because there are two volumes in the products?

Question

Consider the gaseous equilibrium
$$2HI(g) \rightleftharpoons
 H_2(g) +I_2(g)$$

the addition of more hydrogen will shift the equilibrium to the left right? If yes I don't get why; because there are two volumes in the products?

apoorvk · Answer

The addition of more hydrogen would shift the reaction towards the reactant side, since you;re adding more 'product'.

apoorvk · Answer

Oh you mentioned 'left' - I only noticed the 'right' beside it. My bad lol.

unklerhaukus · Answer

the gas is at lower energy when there are less moles of gas {ie less pressure

the gas pressures are stable when there are as many moles of reactant/products

anonymous · Answer

then it shift to the left or right?

unklerhaukus · Answer

if you add to the right, some will move to the left

anonymous · Answer

the hydrogen would move to the left( reactants)?

apoorvk · Answer

The basic funda is that, since more hydrogen has been added, the collision frequency between hydrogen and iodine molecules would increase, and hence, the reformation of HI would be get a 'push', and hence the equilibrium 'shifts towards left' a bit!

anonymous · Answer

i got it; thanks