Question

a
The screams from the roller coaster were being measured that day. Our normal speaking sound level is measured 50 decibels (dB). The screams from ‘Leviathan’ were measured at 110 dB. How much more intense is the screams from the Leviathan than our normal sound level.

Answer 1

i think you just subtract 50 from 110.

110-50=?

Answer 2

@kaiz122 : i guess, probably percentage may required..

Answer 3

no. i have to use sound equation. but i dont know how

Answer 4

oops, m not aware of that.. if u can provide eqtn from book.. than we might be able to help u...

Answer 5

L= 10log(I/I\[L= 10 \log ( I/Io )\]

Answer 6

so, L = 10 log (110/50)

i guess, Io is normal decibel, while I is increased decibel..

can u calculate further.. You may use calculator..

Answer 7

if m right, than it would be L = 7.88..

with its units...

Answer 8

but some one said it is 1000000000 more instanse how do u get that

Answer 9

wow... i have no idea.. sorry !!!

Answer 10

no one help. i need it my today :(

Answer 11

i wished i could.. ohkey, lets ask to some genius minds over here..

@ParthKohli , @waterineyes , @ganeshie8 ... Guys can anyone help, plz ??

Answer 12

Sorry no clue.. @Ganpat

Answer 13

thnakx for the help Ganpat its ok

Answer 14

50 = 10 log(I1/Io) ------- (1)
110 = 10 log(I2/Io) -------(2)

Answer 15

you need to take I2/I1
to know how intense is the I2 compared to I1

Answer 16

from (1),

50/10 = log(I1/Io)
=> 5 = log(I1/Io)
=> 10^5 = I1/Io
=> I1 = Io x 10^5 ------------------(3)

Answer 17

from (2),

110/10 = log(I2/Io)
=> 11 = log(I2/Io)
=> 10^11 = I2/Io
=> I2 = Io x 10^11 -----------------------(4)

Answer 18

combine (3) & (4)

and take the ration I2/I1

Answer 19

so lastly Ihow do u do

Answer 20

you mean multiple 3 qnd 4

Answer 21

do (4) / (3)

=>

\(\huge \frac{I2}{I1} = \frac{ Io . 10^{11}}{Io . 10^5} \)

\(\huge = \frac{10^{11}}{10^5}\)

\(\huge = 10^6\)

Answer 22

I2 is 10^6 times more powerful than I1

Answer 23

thank youu soo much

Answer 24

yw =))