Find the n th term and sum of n terms of the series 5 + 8 + 17 + 44 ..........
Ah, this is a nice series. \[[5,8,17,44]\]
find the difference .. note the difference in the difference is a multiple of 3
Yes the first order difference is in Gp
and on...so do as @experimentX suggests, first examine any sort of relationship that could exist, you see that each termer is greater than the next
I suggest that you show us the values you have for the difference between the numbers in the series
Once, you have those differences, see if there is a pattern or relationship among them
Looks like 3 to some power :D
tn+1 = tn + 3^(n-1)
term1 = 5 term2 = 8 term2 - term1 = 3 so term2 = term1 + 3 term3 = 17 term3 - term2 = 9 so term3 = term2 + 9 term4 = 44 term5 - term4 = 27 so term4 = term3 + 27 term5 = ...
don't know closed form at the moment!!
So @Yahoo! How are you doing with this?
Ar^n + b1n^k-1 + b2n^k-2............bk
Hmm, can you explain the terms please?
it is the general formula lol1
ok look at the sequence first term is (3^1+7)/2=5 second is (3^2+7)/2=8 third is (3^3+8)/2=17 can you now tell me general formula ?
i guess we should use summation rule |dw:1343147827410:dw|
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