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We have \[\frac{y^2-4}{y+3}=2-\frac{y-2}{y+3}\] Multiply whole equation by y+3, we get \[y^2-4=2(y+3)-(y-2)\] we get \[y^2-4=2y+6-y+2\] Do you get this?
Yeah, but I can't get it all the way simplified.
I'll help you with that combine 2y and -y first on the left side what do you get?
y. I just keep ending up at y^2-4 = y+8 thought.
now bring all the terms to left side
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y^2-y-12?
Do you know quadratic formula?
Ohhhhhhhhhhhhhhhh, thanks. I get it now, haha.
y=4 or y=-3, but it can't make a denominator in the original equation 0, so y=4.
good:D work:D
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