Question

find domain and range of
1-√x

Answer 1

Let:

y = 1 - \(\sqrt{x}\)


now tell me what are the values that x cannot take..

x cannot be negative..

Answer 2

So x must be greater than or equal to zero..

because root of negative number is not defined..

So:

\[x \ge 0\]

This is the domain..

Answer 3

Getting? @dorkkk

Answer 4

how do i get the range? O:

Answer 5

Can you find x in terms of y??

Answer 6

what does range mean exactly?

Answer 7

Subtract 1 both the sides:

y - 1 = - \(\sqrt{x}\)

Square both the sides:

\[x=(y-1)^2\]

Answer 8

Range you can think it as output..

See you have given x as input and you have got output as y or f(x)..

So x is Domain and y or f(x) is range..

Getting??

Answer 9

So in:
\[x = (y-1)^2\]

Here you can give any values to the y the equation will be determined in all the case..

So Range is All Reals..

Answer 10

ahh, okay i get it. thanks!

Answer 11

would i write all real numbers as (∞,∞)?