find domain and range of
1-√x

Question

find domain and range of
1-√x

anonymous · Answer

Let:

y = 1 - $\sqrt{x}$


now tell me what are the values that x cannot take..

x cannot be negative..

anonymous · Answer

So x must be greater than or equal to zero..

because root of negative number is not defined..

So:

$$x \ge 0$$

This is the domain..

anonymous · Answer

Getting? @dorkkk

anonymous · Answer

how do i get the range? O:

anonymous · Answer

Can you find x in terms of y??

anonymous · Answer

what does range mean exactly?

anonymous · Answer

Subtract 1 both the sides:

y - 1 = - $\sqrt{x}$

Square both the sides:

$$x=(y-1)^2$$

anonymous · Answer

Range you can think it as output..

See you have given x as input and you have got output as y or f(x)..

So x is Domain and y or f(x) is range..

Getting??

anonymous · Answer

So in:
$$x = (y-1)^2$$

Here you can give any values to the y the equation will be determined in all the case..

So Range is All Reals..

anonymous · Answer

ahh, okay i get it. thanks!

anonymous · Answer

would i write all real numbers as (∞,∞)?