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Mathematics 7 Online
OpenStudy (anonymous):

8y^3 - 3y^3

OpenStudy (anonymous):

Firstly tell me what is: 8- 3 = ??

OpenStudy (anonymous):

5

OpenStudy (anonymous):

i know the answer but i don't get how

OpenStudy (anonymous):

So attach y^3 with it..

OpenStudy (anonymous):

shouldn't it be just y

OpenStudy (anonymous):

y^3-y^3

OpenStudy (anonymous):

I am explaining you.. Just wait..

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

see: first you know about like terms : 5x, 6x, (1/3)x they are all like terms.. \[6y^2, 7y^2, 8y^2, \frac{1}{5}y^2\] they all are like terms.. Similarly: \[\large 8y^3 - 3y^3\] is like term getting this much ??

OpenStudy (anonymous):

yup..learned that

OpenStudy (anonymous):

So can you factor them or not??

OpenStudy (anonymous):

like: \[\large 8y^3 - 3y^3 = y^3(8-3)\]

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

This step is getting?? I have taken the common term outside..

OpenStudy (anonymous):

yes you have

OpenStudy (anonymous):

\[\large 8y^3 - 3y^3 = y^3(8-3) \implies y^3(5)\] this step you got??

OpenStudy (anonymous):

I have just solved the brackets...

OpenStudy (anonymous):

yes ok i get it................thanks

OpenStudy (anonymous):

Welcome dear..

OpenStudy (anonymous):

In case of like terms just solve them as you are solving real values like 4 - 5 or 5-3 like this.. Simple add or subtract them..

OpenStudy (anonymous):

No they are not like terms..

OpenStudy (anonymous):

there must be y with 5 also.. Then you can subtract them..

OpenStudy (anonymous):

you always take the like terms out?

OpenStudy (anonymous):

But there is not y attached to the 5.. if it was: 8y - 5y \(\implies\) 3y

OpenStudy (anonymous):

got it

OpenStudy (anonymous):

There is no need but to explain you I have taken common that y^3..

OpenStudy (anonymous):

ok...thanks:)

OpenStudy (anonymous):

Welcome dear..

OpenStudy (anonymous):

bi

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