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OpenStudy (anonymous):
Firstly tell me what is: 8- 3 = ??
OpenStudy (anonymous):
5
OpenStudy (anonymous):
i know the answer but i don't get how
OpenStudy (anonymous):
So attach y^3 with it..
OpenStudy (anonymous):
shouldn't it be just y
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OpenStudy (anonymous):
y^3-y^3
OpenStudy (anonymous):
I am explaining you..
Just wait..
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
see:
first you know about like terms :
5x, 6x, (1/3)x they are all like terms..
\[6y^2, 7y^2, 8y^2, \frac{1}{5}y^2\] they all are like terms..
Similarly:
\[\large 8y^3 - 3y^3\] is like term
getting this much ??
OpenStudy (anonymous):
yup..learned that
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OpenStudy (anonymous):
So can you factor them or not??
OpenStudy (anonymous):
like:
\[\large 8y^3 - 3y^3 = y^3(8-3)\]
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
This step is getting??
I have taken the common term outside..
OpenStudy (anonymous):
yes you have
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OpenStudy (anonymous):
\[\large 8y^3 - 3y^3 = y^3(8-3) \implies y^3(5)\]
this step you got??
OpenStudy (anonymous):
I have just solved the brackets...
OpenStudy (anonymous):
yes ok i get it................thanks
OpenStudy (anonymous):
Welcome dear..
OpenStudy (anonymous):
In case of like terms just solve them as you are solving real values like 4 - 5 or 5-3 like this..
Simple add or subtract them..
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OpenStudy (anonymous):
No they are not like terms..
OpenStudy (anonymous):
there must be y with 5 also..
Then you can subtract them..
OpenStudy (anonymous):
you always take the like terms out?
OpenStudy (anonymous):
But there is not y attached to the 5..
if it was:
8y - 5y \(\implies\) 3y
OpenStudy (anonymous):
got it
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OpenStudy (anonymous):
There is no need but to explain you I have taken common that y^3..