Question

find the solution to: 64^(4-x) = 4^(2x) & use complete sentences on how to solve it

Answer 1

Hint:

Rewrite 64 as 4^3 to get


64^(4-x) = 4^(2x)

(4^3)^(4-x) = 4^(2x)


Then multiply the exponents

4^(3(4-x)) = 4^(2x)


Since the bases are equal, the exponents are equal, so...

3(4-x) = 2x

Answer 2

thanks so much (:

Answer 3

you're welcome

Answer 4

tell me what you get for x

Answer 5

3(4-x) = 12 - 3x (i FOILED on that one) then i got 12x - 3x = 2x . subtracted 12x & 3x to get 9x = 2x . then i divided by 2x & got 9/2 = 0 ??? that doesnt work :/ what did i do wrong ?

Answer 6

it should be 12 - 3x and NOT 12x - 3x

Answer 7

So it should be

12 - 3x = 2x

Try it again

Answer 8

oh i added an extra x . so its 12 = 5x . and then 12/5 = x ?

Answer 9

you got it

Answer 10

great ! :D thanks!

Answer 11

sure thing