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Mathematics 9 Online
OpenStudy (anonymous):

Six cards are randomly distributed from a standard pack of 52 playing cards. Determine the probability that exactly one of the 6 cards is a queen.

OpenStudy (ganpat):

so How many queen you have in deck ??

OpenStudy (anonymous):

4

OpenStudy (ganpat):

so, 6 cards out of 52 = 52C6 what it would be ?

OpenStudy (ganpat):

and for a queen out of 6 cards, chances are 6C4 = ??

OpenStudy (ganpat):

do not simplify much... just right a ratio..

OpenStudy (anonymous):

wait but why are the chances for a queen out of 6 cards 6C4? shouldn't the chances be higher?

OpenStudy (ganpat):

we have picked 6 cards from the deck.. and one of them should be queen.. as we have only 4 queen .. the combination would be 6C4...

OpenStudy (anonymous):

why not 6C1?

OpenStudy (ganpat):

oh, i guess m wrong.. it can be 4C1... wait, m confused.. hold on..

OpenStudy (ganpat):

ok, lets start again.. You pick 6 cards from a deck, so that would be 6/52 and one of them should be queen, for that its is 1/4 So the probability of event - 6/52 * 1/4 = 3/104... is this the answer ??

OpenStudy (anonymous):

the answer for ur working is 0.0288 but the textbook answer 0.336

OpenStudy (anonymous):

sorry, I got to go but please type the solution if u get it.

ganeshie8 (ganeshie8):

queen can come exactly in one place. remaining 5 places must have to be filled by other 48 cards

ganeshie8 (ganeshie8):

number of ways of drawing queen for one place = 4C1 number of ways of drawing remaining 5 cards = 48C5 total number of ways of drawing 6 cards = 52C6

ganeshie8 (ganeshie8):

probability of having exactly one queen = \( \frac{4C1 * 48C5}{52C6} \)

OpenStudy (ganpat):

@ganeshie8 : amazing man.. i made same mistake as yesterday... thank u man !! :)

ganeshie8 (ganeshie8):

welcome yaar.. .ty :)

OpenStudy (anonymous):

wait @ganeshie8 why is it 4C1, why is the n only equal to 4 shouldn't it be more?

ganeshie8 (ganeshie8):

you have only 4 queens in the deck. and you want to choose 1 so its 4C1

OpenStudy (anonymous):

so u don't use anything given in the question basically then?

ganeshie8 (ganeshie8):

i didnt get u

OpenStudy (anonymous):

for that part

OpenStudy (anonymous):

4C1

ganeshie8 (ganeshie8):

you have used the "1" thing given in the question

ganeshie8 (ganeshie8):

question says to choose only "1" queen

OpenStudy (anonymous):

but why isn't it 6C1?

ganeshie8 (ganeshie8):

6C1 is : drawing one queen from 6 queens

OpenStudy (anonymous):

yeh I don't know

OpenStudy (anonymous):

I'm just trying to connect all of it together

OpenStudy (anonymous):

dunno, I'm lost but I understand what you did.

OpenStudy (anonymous):

don't worry, I think I got it now.

ganeshie8 (ganeshie8):

think of it like this, 1) First, you pick 1 queen from the available 4 queens - since its a combination, it doesnt matter which place you put in

OpenStudy (anonymous):

sorry, I have to do stuff, so afk.

ganeshie8 (ganeshie8):

its ok... glad to hear u get it :D

OpenStudy (anonymous):

but thanks for having the patience to help me.

OpenStudy (anonymous):

u really deserve more than a medal.

ganeshie8 (ganeshie8):

np

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