Question

Darlene kicks a soccer ball off the ground and in the air with an initial velocity of 34 feet per second. Using the formula H(t) = −16t^2 + vt + s, what is the maximum height the soccer ball reaches?

17.7 feet

18.1 feet

19.3 feet

20.2 feet

Answer 1

i will use calculus based approach

Answer 2

well there is a calculus method; if you know calculus..
differentiate it

Answer 3

Calculate maximum of this function

Answer 4

take derivative to get critical point

Answer 5

derivative is zero on maximum

Answer 6

h'(t)=-32t+v

Answer 7

set equal to zero
-32t+v=0

Answer 8

but v=34 ft/sec given
-32t+34=0

Answer 9

32t=34

Answer 10

soo.,.

Answer 11

t=34/32=1.0625

Answer 12

put t=1.0625 in the original equation

Answer 13

i think there is a typo in the formula..

Answer 14

@Mimi_x3 let me know i do a lot typo mistakes :)

Answer 15

@rebecca1233 can you do this now ?? just put value of t

Answer 16

can you help me so i put 1.0625 in the t spot

Answer 17

not you; the asker \(h(t) = -16t^2 +vt +s\)
there are two unknown variables..

Answer 18

−16t^2 + vt + s,

Answer 19

ok

Answer 20

and if you sub back the t the \(s\) is unknown

Answer 21

ugh can you guys help me with this ..

Answer 22

h(t)=-16(1.0625)^2+34(1.0625+0=

Answer 23

then \(s\) is a constant? and you assume its \(0\)?

Answer 24

let me know the answer @rebecca1233 just calculate the above.

Answer 25

ok i did it
=18.1 feet .
use your calculator.

Answer 26

@rebecca1233