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Physics 7 Online
OpenStudy (unklerhaukus):

is it possible to understand a simple wave without using complex numbers

OpenStudy (anonymous):

\[ \sin(kx - \omega t)\] describes a traveling wave, is that what you mean?

OpenStudy (fwizbang):

f(x-vt), for any function f, is a wave, as is g(x+vt) for any function g. I think the issue you may be having is with functions like e^{ik(x-vt)} which are mathematically simpler "building block" functions that can be used to create the more general cases. They take a little getting used to, but in the long run they make things simpler...

OpenStudy (unklerhaukus):

\[\sin x= \frac{ie^{-ix}+-ie^{ix}}{2}\]

OpenStudy (anonymous):

the derivation of your identity comes from Euler identity \[e^{{i}{\theta}} =\cos(\theta)+isin(\theta)\]

OpenStudy (anonymous):

\[e^{{-i}{\theta}}= \cos(\theta)-isin(\theta)\] hence

OpenStudy (anonymous):

\[\cos(\theta)+isin(\theta)-\cos(\theta)+isin(\theta)= 2isin(\theta)\]

OpenStudy (anonymous):

and so we have \[[{e^{{i}{\theta}}-e^{{i}{\theta}}} ]/ 2i = \sin(\theta)\]

OpenStudy (anonymous):

so they are interchangeable.

OpenStudy (unklerhaukus):

ah yes, because cosine is even

OpenStudy (anonymous):

ops i forgot to put the negative sign into the second value for e also your equation comes by simply multiply \[i/i\]

OpenStudy (anonymous):

\[ i/i * [e^{iθ}−e^{-iθ}]/2i=\sin(θ)\] -->\[-i [e^{iθ}−e^{-iθ}]/2=\sin(θ)\]

OpenStudy (anonymous):

ah yes, because cosine is even .. exactly :)

OpenStudy (nick67):

you can understand many things about waves just looking at the sea :-)

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