How many liters of oxygen gas can be produced if 28.7 grams of water decomposes at 294 Kelvin and 0.986 atmospheres? Show all of the work used to solve this problem.

2 H2O (l) ---2 H2 (g) + O2 (g)

Question

How many liters of oxygen gas can be produced if 28.7 grams of water decomposes at 294 Kelvin and 0.986 atmospheres? Show all of the work used to solve this problem. 

2 H2O (l)  --->2 H2 (g) + O2 (g)

anonymous · Answer

2 H₂O (l) → 2 H₂ (g) + O₂ (g)

1.01 x 2 + 16.00 = 18.02 g/mol
28.7 g H₂O x (1 mol / 18.02g) = 1.59 mol H₂O
water : oxygen = 2 : 1 (mol ratio)
½ x 1.59 = 0.796 mol O₂

V = nRT/P

P=0.986 atm
V=unknown 
n=0.797222 mol O2
R=0.0821
T=294 K


(0.986 atm)V=(0.797222 mol O2)(0.0821)(294 K)
V=19.5 L O2