Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

50% of the data values are within ____ points of the median.

OpenStudy (anonymous):

OpenStudy (amistre64):

hmm, the ends of the box tell us the quartiles

OpenStudy (amistre64):

2 quaters = 50% right?

OpenStudy (anonymous):

yes,

OpenStudy (amistre64):

the box contains what is known as the interquartile range (IQR) which contains 50% of the data; but im not sure how to format that to the question itslef

OpenStudy (anonymous):

Would it be 50% of 23 ?

OpenStudy (amistre64):

no; lets see if the median is the midpoint between the boxend (not the arms) so; is (14+32)/2 = 23 ???

OpenStudy (amistre64):

if so; then the answer would be how far apart 23 is from 14, or 32 ....

OpenStudy (anonymous):

9

OpenStudy (amistre64):

i like 9

OpenStudy (anonymous):

can u help me on another problem too ?

OpenStudy (amistre64):

dunno, i only have a limited amount of smarts that i can conjure up in a day .... do i have it in me?

OpenStudy (anonymous):

lol i believe you do.

OpenStudy (amistre64):

lets give it a shot :)

OpenStudy (anonymous):

The range of the data set is

OpenStudy (amistre64):

range is the distance from the tips of the outstreched arms, or in mathing terms high - low = range

OpenStudy (anonymous):

10-34? so it would be 24

OpenStudy (amistre64):

24 is correct

OpenStudy (anonymous):

:))

OpenStudy (anonymous):

What about stem & left plots..... finding medians ?

OpenStudy (amistre64):

stem and leafs is just a very basic format to organize the data; the median is still the number in the center of it all

OpenStudy (anonymous):

So in this one if would be 54 ?

OpenStudy (amistre64):

hmm, well it is in the 5s you can either add how many data points there are and divide by 2 or start stripping off values from each end till you reach the middle. if i did it right, i think its 57 if you wanna dbl chk me

OpenStudy (amistre64):

5 | 6 7 7 is what i thik im left with and the middle of that is 57

OpenStudy (anonymous):

Now i have a question , how would you get mean out of all that would it be the same ?

OpenStudy (amistre64):

the mean of ALL that is just alot of adding up numbers; then divide by how many numbers there are

OpenStudy (amistre64):

we can work it like this tho: take a row: 3 : 0 1 2 3 4 add up the righties = 10 since there are 5 number to the right; multiply that by the lefty; 5*3 = 15 but, since the lefty is a ten digit; its actually 5*30 ... 150 so add those togeher and we get 160 for the first row ..... not fun, but doable

OpenStudy (anonymous):

im confused ?

OpenStudy (amistre64):

its just adding up all the data points; the first row has data points: 30 31 32 33 34 ----- 160 add up the rest of the rows add them all together to get a grand total and divide by how many numbers there are to begin with

OpenStudy (anonymous):

1736 i got all together now divide them by how many number there are ?

OpenStudy (anonymous):

which i got 56

OpenStudy (amistre64):

ill trust you on that 1736 .. but yes, divide that by how many numbers there are .... which i believe there are 31 of them

OpenStudy (amistre64):

google says 56 is good :)

OpenStudy (anonymous):

but on the answers there is no 56 its only 57 & 54

OpenStudy (amistre64):

double check that 1736 value

OpenStudy (anonymous):

i got the same thing again .

OpenStudy (amistre64):

160 208 379 529 670 ---- 1946 but i did it in my head so its prolly bad 1946/31 gets me to 62.7 hmmm prolly bad head math

OpenStudy (anonymous):

hmm , well we were right because i was looking at the wrong one. :D . now i have another question is that okay ?

OpenStudy (amistre64):

go ahead and post a new one to the left; i have to get back to my paying dayjob :) good luck

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!