Question

What is the equation of the line which includes points (1, 5) and (-2, -7)?

Answer 1

hi :)

Answer 2

helloo

Answer 3

okay so so first you should find the slope of the line [slope= (y2-y1)/(x2-x1)]

Answer 4

try it and tell me what you get :)

Answer 5

how do i find the slopee

Answer 6

[slope= (y2-y1)/(x2-x1)]

Answer 7

??? how did you get that

Answer 8

\[y _{2} - y _{1}\over x _{2}-x _{1}\]

Answer 9

thats the equation to find slope :)

Answer 10

okaii then what

Answer 11

so now you put in the numbers...\[-7-5\over-2-1\]

Answer 12

so i would do -7-5/-2-1

Answer 13

so you combine the terms and get...\[-12\over-3\]

Answer 14

now that can be simplified even more....\[-4\over-1\]

Answer 15

and the negatives get canceled out and the one goes away \[4\]

Answer 16

so now you have your slope :)

Answer 17

im confused because thats not what the question asks

Answer 18

yes but first you need to find the slope to write the equation of the line :)

Answer 19

okay so the equation you need to put it into is \[y=mx+b\]

Answer 20

now you just found m (the slope)

Answer 21

so now choose either one of the two points you started off with :)

Answer 22

(1,5) or (-2,-7) ? :) which one do you want to use??

Answer 23

Let x and y be on the line. Equate the calculation for the slope using the first point and the second point respectively.\[\frac{y-5}{x-1}\text{=}\frac{y+7}{x+2} \]Solve the above for y.\[y=4 x+1 \]

Answer 24

you just...gave..the answer..........

Answer 25

and the method.

Answer 26

Thank you for the medal.

Answer 27

thank yu :) cause i didnt understand a thing he was saying yu made it simple and easy

Answer 28

You're welcome.