is this true? limit of x-->0+ of (x^2+x^3)/(x^3+x^6)=infinity
yes.
are you sure? Why? Can you explain it to me? i am having a hard time understanding it.
when 1/0 = infinity. you know this
by dividing each term by x^6 see what happen
1/5<1/4<1/3<1/2....1/0.5...<1/0.05<...the value become larger when the denominator closer to 0.
So if I understood correctly, this would be only for positive numbers right? For as \[\lim_{x \rightarrow 0} \] instead of \[\lim_{x \rightarrow 0+}\] it wouldn't be true?
if x approach 0 from the left, it will be -ve
-ve? What does that mean?
sorry, its mean negative. it will be negative infinity
|dw:1343261801588:dw|
sorry my bad draw. the graph should look like that i think
Does \[f(g(x))=-\infty \] if f(x)<0 and g(x) = infinity?
emm, dont know.
ok thanks for you're help! I'll add you as a fan! lol I have no many calculus questions, I apologize.
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