is this true? limit of x-->0+ of (x^2+x^3)/(x^3+x^6)=infinity
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (eamier):
yes.
OpenStudy (anonymous):
are you sure? Why? Can you explain it to me? i am having a hard time understanding it.
OpenStudy (eamier):
when 1/0 = infinity. you know this
OpenStudy (eamier):
by dividing each term by x^6 see what happen
OpenStudy (eamier):
1/5<1/4<1/3<1/2....1/0.5...<1/0.05<...the value become larger when the denominator closer to 0.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So if I understood correctly, this would be only for positive numbers right? For as \[\lim_{x \rightarrow 0} \] instead of \[\lim_{x \rightarrow 0+}\] it wouldn't be true?
OpenStudy (eamier):
if x approach 0 from the left, it will be -ve
OpenStudy (anonymous):
-ve? What does that mean?
OpenStudy (eamier):
sorry, its mean negative. it will be negative infinity
OpenStudy (eamier):
|dw:1343261801588:dw|
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (eamier):
sorry my bad draw. the graph should look like that i think
OpenStudy (anonymous):
Does \[f(g(x))=-\infty \] if f(x)<0 and g(x) = infinity?
OpenStudy (eamier):
emm, dont know.
OpenStudy (anonymous):
ok thanks for you're help! I'll add you as a fan! lol I have no many calculus questions, I apologize.