Question

3^(2x-1)=17

Answer 1

can you help?

Answer 2

convert into log form

\[\log_3 17 = 2x - 1\]
add 1 to both sides
\[\log_3 17 + 1 = 2x\]
divide both sides by 2
\[x = \frac{\log_3 17 + 1}{2}\]

Answer 3

got that?

Answer 4

okay but how do I solve it from there?

Answer 5

you use a calculator

Answer 6

it wont let me do log3.. only log10

Answer 7

is the answer 4.7?

Answer 8

idk..i dont have a calculator

Answer 9

how do I do log3 of 17? like how would I type it into the calculator?

Answer 10

\[\log_3 17 \implies \log 17 \div \log 3\]

Answer 11

oh okay, thanks so much for your help

Answer 12

you're welcome