Question

A mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates worth 90¢ a pound. How many pounds of the $1.50 chocolate were used to make the mixture?

Answer 1

x + y = 30
1.50x + .90y = 1.10(30)

Answer 2

^Hint

Answer 3

@zse, are you working on it or are you stumped?

Answer 4

im stuck at this question

Answer 5

I gave you a hint. Have you tried solving the system?

Answer 6

okay i havent done this in a while can you explain:P

Answer 7

You haven't done this in a while? You seem like you've never done it. You should at least know the first step.

Answer 8

Why don't you start by multiplying 1.10(30)

Answer 9

i did that i got 33

Answer 10

Oh, I see. I you meant that 1.10(30) = 33

Answer 11

So now you have

x + y = 30
1.50x + .90y = 33

Answer 12

Now isolate y in both equations

Answer 13

Let me know what you get.

Answer 14

ugh i dont know:(
i forgot i learned this last year

Answer 15

If you have x + y = 30, how difficult is it to subtract x from both sides to get

y = 30 - x

Answer 16

Now isolate y for the second one.

Answer 17

Obviously you have to use algebra to do that. You couldn't possibly have completely forgotten algebra. If you did, you might need to figure out where you hid your brain.

Answer 18

GASP! my friend well obviously i did your smart and you get this stuff im the type of person who has to see how the process goes:/

Answer 19

sorry for waisting your time

Answer 20

To isolate the second equation: 1.50x + .90y = 33, do the following

1. Subtract 1.50x from both sides to get

.90y = 33 - 1.50x

2. Divide both sides by .90 to get:

\(\large y = \frac{33 - 1.50x}{.90}\)

Now you have two equations with y isolated.

Answer 21

What do you think is the next step?

Answer 22

subtract 33 - 1.50x?

Answer 23

How about set y = y ?

Answer 24

You don't seem to have a clue what is going on.

Answer 25

no i dont maybe this website isnt for me since i cant figure it out i mean you know what your doing but i just cant figure it out like i said i need to see how the process goes

Answer 26

Okay, I will show you

Answer 27

on vyew

Answer 28

whats vyew

Answer 29

You'll find out. Click this:

http://vyew.com/room#/418625/Open_Study_Math

Answer 30

Why'd you leave?

Answer 31

its like a tiny chat?

Answer 32

It's an online whiteboard

Answer 33

You said you wanted to see the steps. I will show them to you.

Answer 34

i got it

Answer 35

i mean im on the web