Question

Integral[0,4] x/(sqrt 2x+1) dx

Answer 1

\[\int_0^4 \frac{x}{\sqrt{2x+1}}dx?\]

Answer 2

yes

Answer 3

interesting...

Answer 4

are you allowed to use trig sub?

Answer 5

i know that u= 2x+1

Answer 6

nope

Answer 7

idk about the top x

Answer 8

that would make du = 2dx

Answer 9

that what i thought

Answer 10

have you discussed trigonemetric substitution?

Answer 11

yes

Answer 12

then use trig sub

Answer 13

no that works
u = 2x+1
du = 2 dx

then
x = (u-1)/2

\[\rightarrow \frac{1}{4}\int\limits_{?}^{?}\frac{u-1}{\sqrt{u}} du\]
then split that into 2 fractions

Answer 14

hmm

Answer 15

using the vdu= uv- int u dv

Answer 16

hmm no i wouldn't try integration by parts here

Answer 17

@dumbcow how did u get the u-1?

Answer 18

so it seems you can either do what the dumbcow did or trig sub

Answer 19

\[2x + 1 = u\]
\[u - 1 = 2x\]
\[x = \frac{u-1}{2}\]

Answer 20

let see both them lol

Answer 21

@lgbasallote have you ever herped so much that you derped?

Answer 22

herp derp?

Answer 23

I don't think a trig sub would be useful here.......................................

Answer 24

it would

Answer 25

.................................at all