The finite region bounded by curves y = x2 and y = 4 is rotated about the line y = −2. Sketch the region. Find the volume of the resulting solid.
You can use shells
I have the drawing
oh so I should use 2pi(xi)f(xi)
2pi(2sqrt(yi)(2+yi)delta-y
how do I find the radius?
this site is working terribly for me how did you find the radius
and why 2(y)^(1/2)
x=y^2 so y=sqrt(x) and you need 2*sqrt(x) for the height of a shell
I still don't understand can anyone go over the method??
chinhodado is correct the shell method essentially sums up all the surface areas of the solid, moving from inner side to outer side since we are rotating around a horizontal axis, the integration will be with respect to y because the solid is rotating vertically the center is at y=-2, the radius starts at 2 (distance from y=-2 to origin) then increases until y=4 and radius is 6 , thus radius = y+2 the height is the horizontal distance between 2 points on parabola in terms of y which equals 2x or 2sqrty |dw:1343283025783:dw|
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