Question

evaluate: (i=complex number)
(-3+2i)/8i

Answer 1

@a.galvan2 We know that
\[i^2=-1\]
or
\[\sqrt {-1}=i\]
we have
\[\frac{-3+2i}{8i}\]
Multiply and divide by i
\[\frac{-3+2i}{8i}\times \frac i i\]
now we get
\[\frac{-3i+2i^2}{8i^2}\]
Do you get till here?

Answer 2

so...
3i+2/8?

Answer 3

yeah, you're correct
Good work:D

Answer 4

thank you! I think that's what i did, but was sure it wasn't that easy...

Answer 5

Yeah, it happens sometimes:)