Question

The equation of the circle with center (3, -2) and radius 7 is

Answer 1

equation of a circle is \[(x-h)^2 + (y-k)^2 = r^2\]
where h is the x coordinate of the center
k is the y coordinate of the center
r is radius

Answer 2

is the answer x + y = 51

Answer 3

how did you get that?

Answer 4

maybe a demonstration will help...

Answer 5

EXAMPLE:

center is at (2,3) and radius is 4

\[(x-h)^2 + (y-k)^2 = r^2\]
\[(x - 2)^2 + (y-3)^2 = 4^2\]
\[(x-2)^2 + (y-3)^2 = 16\]
this is now the equation for the one i gave

Answer 6

(x - h)2 +(y-k)2 = r2

(x-3)2 + (y- -2)2 = 49

x-9 + y + 4 = 49

x-5 + y = 49

x+y = 54

Answer 7

(x-3)2 + (y- -2)2 = 49 is this supposed to be the answer

Answer 8

simplify it further... what is y-(-2)

Answer 9

y+4

Answer 10

there...that's the answer \[(x-3)^2 + (y+4)^2 = 49\]