help ASAP!
What is the maximum height achieved if a 0.500 kg mass is thrown straight upward with an initial speed of 85.0 m·s–1? Ignore the effect of air resistance.
saiffffffffffff :))
AlaaaaaaaaaaaaaA :))
o_0
too much screaming my throat hurts x_X
u = 85 a = -10m/s v = 0 s = ? v^2 = u^2 + 2as
The mass in fact doesn't matter, kinetic energy into potential energy.
Oh man! Sorry for the throat.
what is that formula called ?
careful there @saifoo.khan ....
There are 3 basic formulas for motion: http://newton.burney.ws/physics/review/PhysicsEquations/kinematicseqs.gif
@lgbasallote , Ikr. I can smell something wrong too. @Ala123 , let me recheck.
\[E_{kin}=E_{pot}\] \\ \[ \frac{1}{2}mv^2 = mgh\] \[ h= \frac{v^2}{2g} \]
oh
it's actually a physics question so it's not that simple
Conservation of energy.
:DDD
understand what I did?
My brain is in sleep mode. Sorry @Ala123 :(
yea kinda, you cancelled out the mass i see
this is the reason why physics questions shouldnt be put in mathematics group :p lol
haha that's ok @saifoo.khan :D
@saifoo.khan got humiliated because of it
Btw, lgba's photo looks like a goat.
lol xD
yeh @Ala123, gravitation doesn't really like mass in isolated systems, most of the time in cancels out *grins*
i see, my answer is 7225 can you check?
just because I am curious, 85 m/s initial speed? That is so impressing. What a hulk.
LOL.
lol
368.24 meters
definitely not a human being, if you need to add a comment.
wait..what did i do wrong o_0?
Someone from the X-Men maybe.
h=85^2/ 2(.500) isn't it ?
\[ h = \frac{v^2}{2g} = \frac{85^2}{2*9.81} = 368.24 m\]
where the 9.81 came from o_0
I cheated with the units by the way, if you do this in a physics exam, always carry the units with you, sometimes it will help you to see if they cancel and your formula makes sense.
was always there, g = gravitation constant for the earth, 9.81 m/s^2
ohhh g = gravitation? i thought grams wow..... =.=
oh no no, all constants.
In a formula physicist only write constants, if they write units they write it in [brackets] to avoid confusion, doesn't always work though hehe
i see..but this problem is actually my chemistry homework, soo weird o_0
haha, that made me laugh *grins*
:DD
ok let me try the next problem...kinda similar to this, will you check my answer though ?
I will give it a try, sure.
But if it is chemistry, I really can't help hehe, I managed to forget everything so quickly.
If a rock climber accidentally drops a 51.0 g piton from a height of 285 meters, what would its speed be just before striking the ground? Ignore the effects of air resistance.
almost same problem
for this problem..when you write the formula do you just cancelled out the "m" ?
is it okay if I solve it in a physical way?
yeah! the last problem was right.
i got crazy numbers..29070 m.s^-1
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