Question

5X^2-23X+12
Factor the equation. Please show the steps as I do not know how to solve. If I use the quadratic formula to solve does this factor the equation.

Answer 1

5x^2-23X+12

Answer 2

use the quadratic formula

Answer 3

Please remind me of the quadratic formula...

Answer 4

\[x=(-b \pm \sqrt{b^2 - 4ac}) \div 2a\]

memorize this like it's your phone number: you need this when the leading coefficient with the highest factor is but 1

Answer 5

still confused

Answer 6

a=5, b=-23, c=12
apply this number into the formula...
then u will get X=4 OR 3/5

Answer 7

terminology to learn: coefficient

Answer 8

That is to solve the problem, I need to factor

Answer 9

yeah and quadratic formula is used to factor quadratic equations containing leading coefficients >1

Answer 10

here's the answer (5x-3)(x-4)

another way to do factoring is the AC method

Answer 11

Can you please tell me what the AC method is...

Answer 12

were you taught what the AC method is?

Answer 13

No I am an entering pre calc student

Answer 14

AC method factoring is an introductory algebra topic

Answer 15

http://www.purplemath.com/modules/factquad.htm

Answer 16

Thank you....

Answer 17

waiiitt but this problem is diff since our A isnt one but our A is 5

Answer 18

A=5 and C=12
So we multiply our A by C which is 5*12=60
now at this point we need to find to numbers that when u add them it equals 23 and when u multiply them equals 60

Answer 19

so -3*-20=60
and -3+(-20)=-23

Answer 20

now we go back to our usual method and replace our middle term with these 2 new terms:
\( 5x^2 -20x -3x +12\)
\( 5x(x-4)-3(x-4) \)
\( (5x-3)(x-4) \)

Answer 21

And VOILA there is your answer

Answer 22

that answer has been given but thank you for the steps :)

I posted a link so the person delves into it more and try to learn it instead of relying on other people solving

Answer 23

idk this stuff can be hard to understand when someone isnt teaching it to u. It can get a wee bit confusing so when i read the link i decided to be nice

Answer 24

these kind of problems aren't thrown from out of nowhere to students. they are introduced first.

Answer 25

got it now the website helped.....

Answer 26

YAYYYYYYYYYYY :DDDDD

Answer 27

great! now demand a reimbursement from your professor or teacher for having failed to teach you this.

Answer 28

hahahahah

Answer 29

public school? that's from the lot of parents' taxes