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A firecracker shoots up from a hill 165 feet high with an initial speed of 110 feet per second. Using the formula H(t) = −16t2 + vt + s, determine how long it will take the firecracker to hit the ground. 7.2 seconds 7.5 seconds 7.8 seconds 8.1 seconds
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You have an initial condition where H(0) = 165. This will help you solve for s. You also know that the initial velocity (v) = 110ft/s. You just need to solve for the final time (lets call it f) when H(f) = 0.
H(0) = -16(0)^2 + 110(0) + s = 165 Can you see what s must be? H(f) = -16(f)^2 + 110(f) + s = 0
I am assuming the firecracker lands somewhere 165 feet below the place it was fired from.
I'm getting it so far.
Wait so whats the answer?
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8.1 D
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