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factoring 2x^2 - 7x - 4 = 0 ?? for some reason I'm stuck on this one.. I need to find the solutions.
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\[2x^2 - 7x - 4 = 0\] break down the middle term \[(2x-8x + x - 4 = 0\] factor out \[2x(x - 4) + (x-4) = 0\] factor out again \[(x-4)(2x+1) = 0\] does that help?
yeah the final answer (x - 4)(2x +1) was what I had gotten.. but I need to find the solutions for x after that :/ I know x - 4 = 0 +4 +4 x= 4 but I'm trying to figure out what x equals for (2x + 1) thank you
\[2x + 1 = 0\] \[2x = -1\] \[x = -\frac 12\]
got it?
ohh so it turns into a fraction.. Okay thank you :)
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