factoring 2x^2 - 7x - 4 = 0 ?? for some reason I'm stuck on this one.. I need to find the solutions.

Question

lgbasallote · Answer

$$2x^2 - 7x - 4 = 0$$
break down the middle term
$$(2x-8x + x - 4 = 0$$
factor out
$$2x(x - 4) + (x-4) = 0$$
factor out again
$$(x-4)(2x+1) = 0$$
does that help?

happinessbreaksbones · Answer

yeah the final answer (x - 4)(2x +1) was what I had gotten.. but I need to find the solutions for x after that :/ 
I know x - 4 = 0
             +4    +4
x= 4
but I'm trying to figure out what x equals for (2x + 1)
thank you

lgbasallote · Answer

$$2x + 1 = 0$$
$$2x = -1$$
$$x = -\frac 12$$

lgbasallote · Answer

got it?

happinessbreaksbones · Answer

ohh so it turns into a fraction.. Okay thank you :)

lgbasallote · Answer