simplify (sqrt(x^2-x)-x)* (sqrt(x^2-x)+x/(sqrt(x^2-x)+x)
\[\large (\sqrt{x^2 - x} - x )\times \frac{\sqrt{x^2 - x} + x}{\sqrt{x^2 - x} +x}\] isnt this just times 1?
exactly, but I meant, but what does it equal at the end?!
it's not times one. It's time the congent.
\[\implies (\sqrt{x^2 - x} - x) \times 1\]
did i write your question right?
\[\large \frac{\large (\sqrt{x^2 - x} - x )\times \sqrt{x^2 - x} + x}{\sqrt{x^2 - x} +x}\]
Although the answer will be same..
yes, exactly, but now what? How does one solve such a problem?
\[b \times 1 = b\] anything multipliedto 1 remains the same
the answer will not be the same. It will remove the square roots
\[\large \frac{\large (\sqrt{x^2 - x} - x )\times \cancel{\sqrt{x^2 - x} + x}}{\cancel{\sqrt{x^2 - x} +x}}\]
OHHHH conjugate...
yes! that's the word!
you dont really do conjugate in this situation...but if you insist...
if I did it wrong then tell me.
What is your actual question ??
the first part of the equation times the conjugate.
\[\large (\sqrt{x^2 - x} - x )\times \frac{\sqrt{x^2 - x} + x}{\sqrt{x^2 - x} +x} \implies \frac{x^2 - x - x^2}{\sqrt{x^2 - x} +x}\]
\[\frac{(\sqrt{x^2 - x} - x)(\sqrt{x^2 - x} + x)}{\sqrt{x^2 - x} + x}\] \[\implies \frac{(\sqrt{x^2 - x})^2 - (x)^2}{\sqrt{x^2 - x} + x}\] \[\implies \frac{ x^2 - x -x^2}{\sqrt{x^2 - x} + x}\] \[\implies \frac{-x}{\sqrt{x^2 - x} + x}\]
\[\large (\sqrt{x^2 - x} - x )\times \frac{\sqrt{x^2 - x} + x}{\sqrt{x^2 - x} +x} \implies \frac{x^2 - x - x^2}{\sqrt{x^2 - x} +x} \implies \frac{-x}{\sqrt{x^2 - x} +x}\]
okay i encountered some problems coz i couldnt see the live preview of the latex =)))
Just reload the page..
do you get what i did @Compgroupmail
yes, just absorbing it now.
alright thanks. I got it now. :)
water, what tool do you use in displaying the equations?
wonderful
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