A company's monthly profit, P, from a product is given by P = −x2 + 105x − 1050, where x is the price of the product in dollars. What is the lowest price of the product, in dollars, that gives a monthly profit of $1,550?
substitute $1550 for P then just factor out the equation o.0
so 1550 = -x^2 + 105x - 1050? And then do i factor -x^2 + 105x - 1050?
yep :D
the you would get two zeros so pick the one with the least value and also it cannot be negative
then*
wait what?! :o
wait hold on.... is the original equation P = −x2 + 105x − 1050?
yes
then the equation you need to factor out is −x2 + 105x − 2100=0
ah well just solve it out with whatever method you want and tell me what you get
but no factors of -2100 are the sum of 105? i think..
do you know what the answer is? @alexwee123
May I help you ??
yes please :)
You have given P = 1550: Plug this value in: \(1550 = -x^2 + 105x - 1050\) So: \(x^2 - 105x + 2600 = 0\) You have to solve this quadratic equation..
Here a = 1, b = -105 and c = 2600 Find Discriminant here: \(D = b^2 - 4ac\) \(D = 11025 - 10400\) = ??
So you will get like 625 after subtracting them right ??
\[D = 625 \implies \sqrt{D} = 25\] Right ??
yes correct!
oh well i factored the equation x^2 - 105x + 2600 = 0 and got (x - 65) ( x - 40?
(x - 65) ( x- 40)
I did the method where you take the factors of 2600 that are the sum of -105
Great well done..
\[(x-65)(x-40) = 0\] So, x = 65 and x = 40 you will get..
i'm confused :o
How ??
oh no okay i understand! did you make x - 65 = 0 and x - 40 = 0? Then you get x = 65 and x = 40 right?
Yes I did the same..
oh ok so then is the final answer 40?! :o
Yes it is..
ok thank you :D
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