Question

Help! Which of these is equivalent to log(3y)*2x

a.) log(2x)/log(3y)
b.) log(3y)/log(2x)
c.) log*2x/3y
d.) log*3y/2x

Answer 1

Also how would you find out?

Answer 2

do you mean \[\LARGE \log_{3y} 2x\]

Answer 3

yes, how would you usually write it?

Answer 4

it's written log_(3y) (2x)

Answer 5

ohh okay

Answer 6

anyway...you use change-of-base formula
\[\huge \log_a b = \frac{\log_c b}{\log_c a}\]
for example you have \[\large \log_x 2\]
i can rewrite this as\[\Large \frac{\log_y 2}{\log_y x}\]
or simply \[\Large \frac{\log 2}{\log x}\]
does that give you any ideas?

Answer 7

so its a!

Answer 8

YES!!!

Answer 9

yaay thank you!

Answer 10

you're welcome ^_^

Answer 11

wait I have one more question and I think it's basically the same

Answer 12

Which of the following is equivalent to log_(7) (50) rounded to three decimal places?

a.) 2.010

b.) 1.772

c.) 0.854

d.) 0.497

Answer 13

do you do it the same way because in that case it would be 7.14 but those aren't one of the options

Answer 14

\[\log_7 (50) = \frac{\log 50}{\log 7} \implies \log 50 \div \log 7\]
is that what you did?

Answer 15

yeah

Answer 16

isnt that what youre supposed to do

Answer 17

actually... i think what you did was \(50 \div 7\)

Answer 18

recheck what you did in your calculator

Answer 19

ohhhhhh you have to put the log sign in?

Answer 20

lol of course =)) \(\log 50 \div \log 7\) exactly that

Answer 21

ya its a

Answer 22

thank you for your help but will you maybe help me with one more thing?

Answer 23

i'll try

Answer 24

To find out how long it will take for $500 to double when invested at 5% annual interest compounded twice a year, you solve the following equation: 1000 = 500 (1+(.05/2))^2t. Use complete sentence to describe each step of math needed to solve this equation.

Answer 25

I already did it but I feel like i did it really wrong..

Answer 26

ugh sorry im not good with "compounded" thingies

Answer 27

i dont know that

Answer 28

okay no probs thankyou!