Question

Find the product. -7(-a^2)^2(-b^3)

i need help, step by step.

Answer 1

After you @lgbasallote

Answer 2

accoding to PEMDAS start with exponent so what is \[(-a^2)^2?\]

Answer 3

-a^4

Answer 4

not exactly...maybe this will help \[(-2)^2 = 2^2 = 4\]
because \[(-2)^2 \implies -2 \times -2\] and negative times negative is positive.

does that make sense?

Answer 5

oh ok, yes

Answer 6

so what's \[(-a^2)^2\]

Answer 7

four

Answer 8

how did you get 4?

Answer 9

do i do four times -7 now?

Answer 10

no...you're doing \[(-a^2)^2\] im asking how that became 4

Answer 11

oh..
a^4

Answer 12

right

Answer 13

so you have \[-7(a^4)(-b^3)\]
what is 7 times a^4?

Answer 14

7a^4?

Answer 15

uhh correction.. what's -7 times a^4

Answer 16

forgot to put my negative sign

Answer 17

-7a^4.

Answer 18

right so now you have \[(-7a^4)(-b^3)\]

Answer 19

what would be the product?

Answer 20

so isit 7a^4b^3?

Answer 21

yup

Answer 22

thank you!

Answer 23

you're welcome!