It is claimed that two cesium clocks, if allowed to run for 100 years, free from any disturbance, may differ by only about 0.02 s. What does this imply for the accuracy of the standard cesium clock in measuring a time-interval of 1 s?

Question

vincent-lyon.fr · Answer

This ratio is non-dimensional, but expressed with different units in num and denom.

Convert to 'second per second' and you will get your answer.

ganpat · Answer

In 100 years.. 1 leap year every day in every 4 yrs.. 
so 24 leap years + 76 years

1 year = 365 days..
1 leap year = 366 days...

24 (366) + 76 (365) =  36524 days..

Now calculating Number of seconds

36524 * 24 * 60 = 52594560 seconds in 100 years...

So, 52594560 seconds ---->  0.02 sec error..
                    1 second -----> x error..

So x = 0.02 / 52594560 = 3.802 e to the power -10..


Error per sec for Cesium clock = 3.802 e to the power -10..

Just a try...

ganpat · Answer

the error would be 

+/-  3.802 e to the power -10..

ganpat · Answer

is that right ??

vincent-lyon.fr · Answer

@Ganpat
You have mistaken minutes and seconds in your calculation.

ganpat · Answer

ya, i guess.. need to multiply more by 60, however method would remain same.. anyways thanks @Vincent-Lyon.Fr ...