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Simplify. n^6 · n^5 · n^4 ÷ n^3 · n^2 ÷ n isn't the answer n^9?
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No I don't think so..
can you help me to figure it out?
Solve one by one: \[\large n^6 .n^5 = ??\]
n^11?
Yes.. Now: \[\large \frac{n^4}{ n^3} = ??\]
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Just subtract the powers..
n^1?
Yes.. \[\large \frac{n^2}{ n} = ??\]
n^1?
So combine all the results now what did you get on combining??
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Combine all the three results you got...
\[\large n^{11} \times n^1 \times n^1 = ???\]
Use the formula BODMAS B=BRACKET O=OF D=DIVISION M=MULTIPLICATION A=ADDITION S=SUBTRACTION
n^13?
Yes well done..
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thank you!
Welcome dear..
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