Question

write a c++ prgm to read a number and its cube ?

Answer 1

@nick67

Answer 2

@Yahoo!
could you better explain what the program has to do ?

Answer 3

we have to set a number eg a=10 and the otput should be its cube

Answer 4

but where is the difference with the previous program ?

Answer 5

in 1 st one we have nt set any number

Answer 6

in 1 st one it is cin

Answer 7

we can enter any number

Answer 8

well, I'm a little confused; in the previous program you can enter any integer and it shows the cube of that number

Answer 9

but in this we should set a number and show its cube

Answer 10

example if we set a= 10 the out put should be a*a*a = 1000

Answer 11

so, in this program we don't have any input ? Output only ?

Answer 12

Why C++? This basic thing could be written in C.

Answer 13

@nick67 no.........we should insert a input

Answer 14

double number;
double result;

scanf("lf", %number);

result = number ^ 3;

printf("This number cube is " %lf, number);

Answer 15

@zepp i want this in C++

Answer 16

@Yahoo!
so this is the previous program :-)

Answer 17

No!!

Answer 18

previous prgm we dont have an input such as a=18

Answer 19

sorry, I can't catch the difference :-(

Answer 20

in this we should give an input and find its cube

Answer 21

the input in the previous program is the instruction: "cin >> value"
and the user can enter any value with the keyboard

Answer 22

YuP ..........Here we xant enter any number it should only display the cube of input number

Answer 23

#include <iostream>
using namespace std;

int main()
{
double number(0) // Declare variables
cout << "Enter a number" << endl;
cout << ">>>"; //Store number in the variable number
cin >> number;
double const resultat(number^3);
cout << This number cubed << " = " << resultat << endl; // Display result
return 0;
}

Haven't done C++ in ages :S

Answer 24

@zepp not this much i need a simple prgm

Answer 25

That's simple D:

Answer 26

@zepp i need such a prgm #include <iostream>
using namespace std;

int main()
{
int value, cube;
cin >> value;
cube = value*value*value;
cout << cube;
return 0;
}

Answer 27

here we can enter any number and it will show its cube

Answer 28

..That's what I did.

Answer 29

i want a prgm to chow cube of given number

Answer 30

@zepp u have enterned many things

Answer 31

@zepp i am new to C++ thats why>....

Answer 32

Those are comments lol

Answer 33

cant u remove all those comment and paste that with input such as a=10

Answer 34

int main()
{
int n=18;
int cube = n*n*n;
cout << cube;
return 0;
}

Answer 35

@Yahoo!
if you execute the previous program (the one you closed the question) and you enter as input the number 10 it shows you as output the number 1000

Answer 36

#include <iostream>
using namespace std;

int main()
{
int value(0), cube(0); // Declare variables here

cout << "???" << endl; // Here we are going to ask the user to enter a number

cin >> value; // Store the value you've just entered in the variable value

int cube = value * value * value; // Do the operation

cout << Cube; // Display result

return 0;
}

Answer 37

If you don't like comments then...

#include <iostream>
using namespace std;

int main()
{
int value(0), cube(0);
cout << "???" << endl;
cin >> value;
int cube = value * value * value;
cout << Cube;
return 0;
}

comments are useful if you want to double check your code (big program takes thousand line), it's quite useful.

Answer 38

Sorry, lowercase C in cube, C/C++ are case sensitive.

#include <iostream>
using namespace std;

int main()
{
int value(0), cube(0);
cout << "???" << endl;
cin >> value;
int cube = value * value * value;
cout << cube;
return 0;
}

Answer 39

thxxx guys))).............@zepp , @nick67 , @rsadhvika

Answer 40

yw

Answer 41

@Yahoo!
you're welcome

Answer 42

@zepp
just a few questions:
why did you declare "value(0), cube(0)" instead of "value, cube" ?
and why did you declare again "int cube" ?
:-)

Answer 43

int cube was to calculate the cube of value

Answer 44

and value(0), cube(0) doesn't change anything, it only stores 0 first;

Answer 45

are you sure this sintax is correct ?

Answer 46

You can always check :)

Answer 47

I mean, can you declare again "int cube" after it's first declaration ? gcc gives error

Answer 48

I'm pretty sure I can

Answer 49

um, I did that with a const, maybe it won't work :s

Answer 50

I have this on gcc:
error: redeclaration of ‘int cube’
error: ‘int cube’ previously declared here

Answer 51

try int const cube = value * value * value; instead?

Answer 52

but why re-declare cube? it's been already declared before

Answer 53

notice 'const'

Answer 54

ok, thank you

Answer 55

@nick67 Sorry, it shouldn't be declared twice, my bad.

Answer 56

http://puu.sh/M9lF