Question

What is the sum of the multiples of 3 between 3 and 999, inclusive?

Answer 1

n = 333

\[\large Sum = \frac{333}{2}(3 + 999)\]

Answer 2

3n = 999

n = 333...

Answer 3

for the first thing you told me to solev i got 5511

Answer 4

\[\large Sum = \frac{333}{2}(3 + 999)\]

Answer 5

and i got 166,833 for the second one

Answer 6

Solve this thing..

Answer 7

Yes second one is right..

Answer 8

so thats the answer?

Answer 9

3 + 6 + 9 + ........................+ 999


a = 3 d= 3 and last term is 999:

999 = 3 + (n-1)(3)

999 = 3n

n = 333..
So use this:

\(\large Sum=\frac{333}{2}(3+999)\)

Answer 10

Why??
Do you have any doubt in that??

Answer 11

no.... i have to know the answer obviously thats why

Answer 12

before i put it down and its wrong

Answer 13

That is the right answer..

Answer 14

ohk great! thanks so much!

Answer 15

Welcome..