Question

plz help, and explain. I will up load pic.
I think the answer is 1/(x-3)(x+4) or 1/(x+4)(x-5)

Answer 1

factorise (x2 + x -12)

can u do that ??

Answer 2

Ans. is 1/(x+4). since (x^2+x-12)=(x+4)(x-3) then (\[(x-3)/((x+4)*(x-3))\]=1/(x+4)

Answer 3

yes that is what she said , but I have two problems that are the same. one was 1/(x-3)(x+4) and 1/(x+4)(x-5). One person said on my last post that t was 1/(x-3)(x+4)?

Answer 4

it*

Answer 5

is that the right answer???

Answer 6

Yo check do this: (x^2+x-12)=0 ->
if (x-3)=0->x=3 -> 3^2+3-12=0 ,
if (x+4)=0->x=-4->(-4)^2-4-12=0
but x=5 5^2-5-12=8 not 0

Answer 7

x2 + x -12 = 0
x2 + 4x - 3x -12 = 0
x (x+4) -3 (x +4) = 0
(x +4)(x -3) = 0

So (x-3) / (x +4)(x -3)

= 1/ (x+4)...