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Mathematics 11 Online
OpenStudy (happinessbreaksbones):

Word Problem in comments.. Please help :(

OpenStudy (happinessbreaksbones):

The smallest piece there is of any substance is called a molecule. A single water molecule is the smallest thing that can still be called water. It is small. Very small. It is so very small that the typical half-liter water bottle holds about 16,700,000,000,000,000,000,000,000 water molecules. Just to get an idea of why scientific notation is important, try writing 16,700,000,000,000,000,000,000,000 ten times without getting frustrated. Now write 1.67 x 1025. It is easier, right? There is a rule that lets us calculate how much of a substance takes up a particular space. According to this rule, 18 grams of water contain a total of 6.02x1023 molecules of water. It looks like a lot, but consider that 18 grams weigh only about 2/3 of one ounce and fill less than half an inch in a half-liter water bottle. Again, the rule is that 18 grams of water contains about 6.02*1023 water molecules. Question #1: Consider Bob, who weighs 180 pounds. On Earth, a kilogram weighs 2.2 pounds, and just for reference, a kilogram is one thousand grams. About 60% of a person is water. Approximately how many molecules of water are in Bob? Give your answer in scientific notation rounded to the nearest hundredth and in standard notation. SHOW THE STEPS USED TO FIND THESE VALUES IF YOU WISH TO RECEIVE CREDIT.

OpenStudy (happinessbreaksbones):

Question #2 Now you will go backwards. Consider Irene, who has about 1.28*1027 water molecules in her. How much does she weigh? Round to the nearest hundredth of a pound. REMEMBER TO SHOW ALL STEPS

jimthompson5910 (jim_thompson5910):

They say that "the rule is that 18 grams of water contains about 6.02*1023 water molecules" So you need to convert 180 pounds to grams

jimthompson5910 (jim_thompson5910):

how do we do this?

jimthompson5910 (jim_thompson5910):

any ideas?

OpenStudy (happinessbreaksbones):

I was thinking maybe dividing, but I wasn't sure :(

jimthompson5910 (jim_thompson5910):

In the problem, we're given this 1 kilogram = 2.2 pounds 1 kilogram = 1000 grams we'll use these two facts to convert from pounds to grams First convert 180 pounds to kg (180 pounds)*(1 kilogram/2.2 pounds) = 180/2.2 = 81.818181818 kilograms So 180 pounds = 81.818181818 kilograms Now convert this to grams (81.818181818 kilograms)*(1000 grams/1 kilogram) = 81.818181818*1000 = 81818.181818 grams So 81.81818 kilograms = 81818.181818 grams (roughly) ------------------------------------------------------- This means that 180 pounds = 81818.181818 grams (roughly)

jimthompson5910 (jim_thompson5910):

So if Bob weighs 180 pounds, then he also weighs about 81818.181818 grams

jimthompson5910 (jim_thompson5910):

How much of this weight (in grams) is water?

OpenStudy (happinessbreaksbones):

wow interesting.. Hmm 60% of his weight

jimthompson5910 (jim_thompson5910):

so 60% of 81818.181818 grams is...?

OpenStudy (happinessbreaksbones):

49090.90909? I hope that's right.. I'm not really good at percentages.

jimthompson5910 (jim_thompson5910):

that's correct

OpenStudy (happinessbreaksbones):

thank you so much

jimthompson5910 (jim_thompson5910):

So Bob is composed of roughly 49090.90909 grams of pure water

OpenStudy (happinessbreaksbones):

awesome

jimthompson5910 (jim_thompson5910):

Now you can use this to figure out how many molecules of water are in Bob

OpenStudy (happinessbreaksbones):

okay thank you Jim :)

jimthompson5910 (jim_thompson5910):

sure thing

jimthompson5910 (jim_thompson5910):

and it might be easier to convert 49090.90909 to scientific notation to get 4.909 x 10^4

jimthompson5910 (jim_thompson5910):

since the number is an approximation, you can get away with dropping a few decimal places

OpenStudy (happinessbreaksbones):

yeah, I almost forgot about that thank you again, you are great

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (happinessbreaksbones):

So, 60% of his weight in grams, 81818.181818, is 49090.90909.. Scientific Notation: 4.909 x 10^4 SO, if 18 grams of water contains about 6.02 x 10^23 water molecules, then 6.02 x 10^23 divided by 4.909 x 10^4 equals 1.226296296 x 10^19 so there are 1.226296296 x 10^19 molecules of water in Bob.. I hope that is correct.. wasn't sure if I should divide or multiply

jimthompson5910 (jim_thompson5910):

18 grams of water = 6.02 x 10^23 water molecules So since we want to find out how many molecules of water are in 4.909 x 10^4 grams, we do the following (4.909 x 10^4 grams)*(6.02 x 10^23 water molecules/18 grams) (4.909 x 10^4 grams)*(6.02 x 10^23 water molecules/1.8 *10^1 grams) (4.909 x 10^4 grams)*(3.344444 x 10^(23-1) water molecules/1 gram) (4.909 x 10^4 grams)*(3.344444 x 10^22 water molecules/1 gram) 4.909 x 10^4 * 3.344444 x 10^22 (4.909* 3.344444) x (10^4 * 10^22) 16.417875596 x (10^4 * 10^22) 1.6418 x 10^1 x (10^4 * 10^22) 1.6418 x (10^1*10^4 * 10^22) 1.6418 x (10^(1+4+22) ) 1.6418 x 10^(27) So in the end, there are roughly 1.6418 x 10^(27) water molecules in 4.909 x 10^4 grams of water This rounds to 1.64 x 10^(27) when rounding to the nearest hundredth =============================================== Question: Approximately how many molecules of water are in Bob? ------------------------- Answer: Approximately 1.64 x 10^(27) molecules of water

OpenStudy (happinessbreaksbones):

Oh wow, I was far off lol thank you.. and so I'm guessing that for the second question: "Question #2 Now you will go backwards. Consider Irene, who has about 1.28 x 10^27 water molecules in her. How much does she weigh? Round to the nearest hundredth of a pound. REMEMBER TO SHOW ALL STEPS" I would possibly have to divide 1.28 x 10^27 by 6.02 x 10^23/18 grams ?

jimthompson5910 (jim_thompson5910):

Use the conversion factor 18 grams = 6.02 x 10^23 molecules so... (1.28 x 10^27 water molecules)*(18 grams/6.02 x 10^23 molecules) and tell me what you get

jimthompson5910 (jim_thompson5910):

doing this calculation will give you an answer in grams from there, you convert to kilograms, then to pounds

OpenStudy (happinessbreaksbones):

Okay thank you so much, i'll tell you what I get.

jimthompson5910 (jim_thompson5910):

alright sounds great

OpenStudy (happinessbreaksbones):

hmm I'm not so sure about my answer.. I got: (1.28 x 10^27)(18 grams/6.02 x 10^23) 2.304 x 10^28 /6.02 x 10^23 3.827242525 x 10^50

jimthompson5910 (jim_thompson5910):

1.28 x 10^27 * 18 1.28 x 10^27 * 1.8 x 10^1 (1.28*1.8) x (10^27 * 10^1) 2.304 x 10^28 So you got that part correct ------------------------------- (2.304 x 10^28)/(6.02 x 10^23) (2.304/6.02) x (10^28)/(10^23) 0.3827242524917 x 10^5 ... This is where you made your error 3.827242524917 x 10^(-1) x 10^5 3.827242524917 x 10^4 ----------------------------------------- So 1.28 x 10^27 molecules tells us that Irene weighs 3.827242524917 x 10^4 grams This is the same as 38,272.42524917 grams Now convert to kg, then convert to lbs

OpenStudy (happinessbreaksbones):

ahh okay that makes much more sense

jimthompson5910 (jim_thompson5910):

Keep in mind that when you get your final answer in pounds, this answer will be her water weight only (this won't be her actual weight). So you'll then use the fact that she's roughly 60% water to find her true weight.

jimthompson5910 (jim_thompson5910):

I nearly forgot about that

OpenStudy (happinessbreaksbones):

Thank you so much for all your help lately.. I do online schooling and none of my teachers are really reliable for help :/ I'm trying to get a few projects done by midnight.. the deadline of my class.. if I get stuck again and you're not busy, could I ask for your assistance? Thank you

jimthompson5910 (jim_thompson5910):

sure you can ask me any time you want

jimthompson5910 (jim_thompson5910):

I'm glad I could be of help

OpenStudy (happinessbreaksbones):

okay thank you :)

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (happinessbreaksbones):

3.827242524917 x 10^4 /1000 38.27242525 • 2.2 84.19933555 lbs of water?

OpenStudy (happinessbreaksbones):

hmm hopefully that's correct

jimthompson5910 (jim_thompson5910):

one moment

OpenStudy (happinessbreaksbones):

okay take your time

jimthompson5910 (jim_thompson5910):

yes that's correct So Irene has 84.19933555 lbs of water that makes up her entire body weight So what's her total weight?

OpenStudy (happinessbreaksbones):

33.67973422?

jimthompson5910 (jim_thompson5910):

you're going backwards

OpenStudy (happinessbreaksbones):

uh oh lol

jimthompson5910 (jim_thompson5910):

you're not taking 60% of 84.19933555 lbs because you already know the water weight

OpenStudy (happinessbreaksbones):

okay

jimthompson5910 (jim_thompson5910):

You want to take 60% of some unknown total weight, say x, and get 84.19933555 lbs as the result So 0.6x = 84.19933555 now solve for x

OpenStudy (anonymous):

Bob weighs 180 pounds. 180 lb x 2.2 kg/lb = 2.2 x 180 kg He is only 60% water, so that's 0.6 x 2.2 x 180 kg. In grams, that's 1000 x 0.6 x 2.2 x 180 g. Now, to get the number of molecules we do whatever that equals times 6.023 x 10^23 / 18 The best thing to do for such problems is to make sure the units cancel. For example, at the end here we had .. grams x molecules / gram Worry about the units first and the arithmetic second.

OpenStudy (happinessbreaksbones):

@jim_thompson5910 I really hope this isn't incorrect again lol 6.0 (140.3322259) = 84.19933555 x= 140.3322259?

OpenStudy (happinessbreaksbones):

@telliott99 Thank you

jimthompson5910 (jim_thompson5910):

that's 100% correct I did it this way 0.6x = 84.19933555 x = 84.19933555/0.6 x = 140.332225916667 which is exactly what you have

jimthompson5910 (jim_thompson5910):

So Irene is roughly 140.3322259 lbs If you need to round to the nearest pound, then she is roughly 140 pounds

OpenStudy (happinessbreaksbones):

:) yay, thank youuu you are so awesome, I wouldn't of even been able to do this without you

jimthompson5910 (jim_thompson5910):

you're very welcome

jimthompson5910 (jim_thompson5910):

I'm sure you could have

OpenStudy (happinessbreaksbones):

yes 140, now I wont fail my class thank God are you a teacher by any chance?

jimthompson5910 (jim_thompson5910):

I'm a student learning to become one..so half and half i guess

OpenStudy (happinessbreaksbones):

wow thats awesome, well your doing a great job at it :)

jimthompson5910 (jim_thompson5910):

why thank you

jimthompson5910 (jim_thompson5910):

I appreciate the compliment

OpenStudy (happinessbreaksbones):

better than my teacher lol

OpenStudy (happinessbreaksbones):

your welcome, Jim :)

jimthompson5910 (jim_thompson5910):

aww shucks...lol, well I'm sure your teacher is great in his/her own way though

jimthompson5910 (jim_thompson5910):

but you said that you couldn't get a hold of your teacher? that's a bit odd and troubling

jimthompson5910 (jim_thompson5910):

esp when a project is due

OpenStudy (happinessbreaksbones):

yeah, they slack off a lot LOL well i've been doing this online schooling for about 2 years now and have been jumping around from diff. schools, and this one is an alternative so they are a bit different here

OpenStudy (happinessbreaksbones):

but I'm sure I'll be fine, I prefer your help anyways lol

jimthompson5910 (jim_thompson5910):

that's a shame...if the students are meant to work hard, then the teachers should work just as hard (if not work more)

jimthompson5910 (jim_thompson5910):

well that's good, I'm flattered you do lol

OpenStudy (happinessbreaksbones):

lol i agree

OpenStudy (happinessbreaksbones):

well I'm going to try and do my other projects and if I need help I promise to come here lol :)

jimthompson5910 (jim_thompson5910):

alright sounds good lol

jimthompson5910 (jim_thompson5910):

good luck

OpenStudy (happinessbreaksbones):

thank you :)

jimthompson5910 (jim_thompson5910):

sure thing

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