A spherical snowball melts so that its radius decreases from 6 inches to 5.8 inches.
a) Find the approximate change in volume of the snowball.
b) Find the approximate change in the surface area of the snowball.
I think I'm supposed to use linear approximation, can you show me how?

Question

anonymous · Answer

yep

anonymous · Answer

volume of sphere

4/3 pi r^3

take derivative w.r. to radius

dv/dr= 4 pi r^2

dv= 4 pi r^2 dr

anonymous · Answer

now just plug it in

anonymous · Answer

and I do the same with the surface area?

anonymous · Answer

yes, take derivative of surface area formula with respect to radius

anonymous · Answer

Lol it's kind of funny when you think about it because the surface area equation itself is the derivative of volume. Thanks

anonymous · Answer

yep,

fellowroot · Answer

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