Question

Factor the Following Polynomials:

x²-81


x²-13x+36

Which polynomial is a special product and why?

Answer 1

for the first one use
a^2-b^2=(a+b)(a-b)
write
x^2-81=x^2-(9)^2
now use the above formula

Answer 2

let me know. what u got ?

Answer 3

I Don't Get It.

Answer 4

ok

Answer 5

can we write x²-81 as
\[x^2-81=(x)^2-(9)^2\]

Answer 6

reply fast

Answer 7

Yes You Can Write It as that

Answer 8

ok
now using formula
\[a^2-b^2=(a+b)(a-b)\]
write \[(x)^2-(9)^2\]
as
\[(x)^2-(9)^2=(x+9)(x-9)\]
is it oky ?

Answer 9

Yes its okay

Answer 10

ok now for the second one
can i write as
\[x^2-9x-4x-36\] ?
let me know

Answer 11

No you have to change the -36 to +36 at the end so would it be x^2-9x-4x+36

Answer 12

so u are alive:P
ok
\[x^2-9x-4x+36\]
now ok!

Answer 13

ok take common x from the first two terms
and -4 from the last two terms
\[x(x-9)-4(x-9)\]
are u getting this?

Answer 14

@kenya.porter

Answer 15

ok now write above as
\[(x-9)(x-4)\]
these are the factors
hope you got it.

Answer 16

Oh ok so from (x-9) (x-4) you take out the x's which become x^2 and then -9-4=-13and -9*-4=36 which gives me the equation i started with x^2-13x+36

Answer 17

yes

Answer 18

Thank You So Much.

Answer 19

yw:)

Answer 20

:)

Answer 21

It asked for which polynomial is the special product

Answer 22

can't you figure out now?

Answer 23

Would it be x^2-81 ?

Answer 24

yes

Answer 25

because it is standard formula
\[a^2-b^2=(a+b)(a-b)\]

Answer 26

Yes I Understand it that's why that was my answer. Thank you again so much for the help