How many times will the graph of y = –x intersect the graph of y = x2 – 3 ?
Actually, you can equate \(-x\) and \(x^2 - 3\)
equate them to one another \[x^2 - 3 = x\] now solve for x \[x^2 + x - 3 = 0\] now use the discriminant to find out how many positive roots are there \[b^2 - 4ac = 1^2 - 4(1)(-3) \implies 1 + 12 \implies 13\] it's positive therefore there are two roots. therefore it crosses twice
got it?
Since the solution sets will be the same, the point will be the same.. and so we'd have an intersection of those functions.
Why \(x^2 - 3 = x\)? Why not \(x^2 - 3 = -x\)?
uhh typo @_@
\[x^2 - 3 = -x\] solve for x \[x^2 + x - 3 = 0\] now use discriminant to find how many roots are there \[b^2 - 4ac \implies (1)^2 - 4(-3)(1) \implies 1 + 12 \implies 13\] positive so there are 2 roots therefore crosses twice
thanks alot! u shold be a teacher man!
i am haha
oh....well
you are good!
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