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\[3\sqrt{-64}\]
\[\large \sqrt{-64} \implies \sqrt{(-1) \times 64} \implies \sqrt{(-1)} \times \sqrt{64} \implies i8\]
So: \[\large 3 \times i \times 8 = ??\]
whats i?
You can split -64 into factors like this: \[\sqrt[3]{-64}=\sqrt[3]{-1 \times 64}=\sqrt[3]{-1} \times \sqrt[3]{64}\] Then you find the cube root of 64, either by knowing it already or by taking factors. \[\sqrt[3]{64}=\sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2}=2^2=4\] Since the cube root of -1 is -1, the final answer is -1 x 4 = -4.
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