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OpenStudy (anonymous):
A body of mass 1 kg is kept at rest. A constant force of 6.0 N starts acting on it. Find the time taken by the body to move through a distance of 12 m.
13 years ago
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OpenStudy (anonymous):
Help!
13 years ago
OpenStudy (anonymous):
F=ma
f=1 * a= 6n
a=6
s=ut+1/2 at^2
u=0
so find s=1/2 at^2
13 years ago
OpenStudy (anonymous):
okay
13 years ago
OpenStudy (anonymous):
then any hint pls tell
13 years ago
OpenStudy (anonymous):
@lgbasallote
13 years ago
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OpenStudy (anonymous):
help!
13 years ago
OpenStudy (anonymous):
@ParthKohli help!
13 years ago
OpenStudy (anonymous):
help!
13 years ago
OpenStudy (anonymous):
@!Developer! follow theyan
13 years ago
OpenStudy (anonymous):
first find acceleration
13 years ago
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OpenStudy (lgbasallote):
what more do you need?
13 years ago
OpenStudy (anonymous):
and use s = ut + 1/2 a t^2
13 years ago
OpenStudy (anonymous):
then the answer comes 2 s as 't' then how it will come
13 years ago
OpenStudy (anonymous):
12 = 1/2 * 6 * t^2
12*2/6 = t^2
t= 2s
13 years ago
OpenStudy (anonymous):
thanks!
13 years ago
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OpenStudy (anonymous):
Welcome...))
13 years ago
OpenStudy (anonymous):
thanks once again
13 years ago
OpenStudy (anonymous):
it is 24/6= 4 s
13 years ago
OpenStudy (anonymous):
u see it t^2
13 years ago
OpenStudy (turingtest):
this is a physics question
please post questions in their proper category and wait patiently for help
13 years ago
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OpenStudy (anonymous):
t^2 = 4
t = sqrt4 = 2
13 years ago
OpenStudy (turingtest):
@!Developer!
13 years ago
OpenStudy (anonymous):
If u r satisfied plzz give medal!!
13 years ago
OpenStudy (anonymous):
correct!
13 years ago
OpenStudy (anonymous):
I got confused
13 years ago
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OpenStudy (anonymous):
thxxxx
13 years ago
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