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Chemistry 19 Online
OpenStudy (anonymous):

A researcher studying the nutritional value of a new candy places a 6.20-gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.52 °C. If the heat capacity of the calorimeter is 38.90 kJ·K–1, how many nutritional Calories are there per gram of the candy?

OpenStudy (anonymous):

this problem is really hard :O i got like 5 wrongs already :(

OpenStudy (anonymous):

thanks for trying :)

OpenStudy (anonymous):

hey @zbay :D

OpenStudy (anonymous):

\[q=(38.90 \frac{kj}{k})(275.67 k)\] We notice that our kalvin cancel out leaving the answer Kj. We need to use the conversion factor to get from Kj to Cal and then divide by the mass of the candy.

OpenStudy (anonymous):

2562.99 Cal then divide by 6.20

OpenStudy (anonymous):

yes that should get your the energy per gram of candy

OpenStudy (anonymous):

thank you

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